在过滤器中写入如下方法: 复制代码 代码如下: public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { HttpServletRequest httprequest = (HttpServletRequest) request; HttpServletResponse httpresponse = (HttpServletResponse) response; String url = httprequest getRequestURL() toString(); if (httpreq
在过滤器中写入如下方法:
复制代码 代码如下:

public void doFilter(ServletRequest request, ServletResponse response,
FilterChain chain) throws IOException, ServletException {
HttpServletRequest httprequest = (HttpServletRequest) request;
HttpServletResponse httpresponse = (HttpServletResponse) response;
String url = httprequest.getRequestURL().toString();
if (httprequest.getSession()== null) {
if (httprequest.getHeader("x-requested-with") != null
&& httprequest.getHeader("x-requested-with").equals(
"XMLHttpRequest")) { // ajax请求
httpresponse.setHeader("sessionstatus", "timeout");
} else {
httpresponse.sendRedirect("/test/index.jsp");
return;
}
} else {
chain.doFilter(request, response);
}
}

这样,如果session超时,而且是ajax请求,就会在响应头里,sessionstatus有一个timeout;

再用一个全局的方法来处理,session超时要跳转的页面。

jquery 可以用$.ajaxSetup 方法,ext也有类似的方法:
复制代码 代码如下:

//全局的ajax访问,处理ajax清求时sesion超时
$.ajaxSetup({
contentType : "application/x-www-form-urlencoded;charset=utf-8",
complete : function(XMLHttpRequest, textStatus) {
var sessionstatus = XMLHttpRequest.getResponseHeader("sessionstatus"); // 通过XMLHttpRequest取得响应头,sessionstatus,
if (sessionstatus == "timeout") {
// 如果超时就处理 ,指定要跳转的页面
window.location.replace("/test/index.jsp");
}
}
});

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